To find the root between these intervals the limit is divided into parts and stored in the variable m i.e.Īfter the division of limits new interval will be generated as shown in the figure given belowĮxample Input-: x^3 - x^2 + 2 a =-500 and b = 100 Given below is the figure which is showing the intervals f(a) and f(b). Input-: x^3 - x^2 + 2 a =-200 and b = 300Īpproach that we are using in the below program is as follow − Output-: The value of root is : -0.991821 Input the equation and the value of intervals a and b.Divide the intervals as : m = (a + b) / 2 write(,)Enter two numbers a and b simultaneously between which the root is to be.Check if f(a) * f(m) In function double solution(double x). Step 2-> In function bisection(double a, double b) Find out the Fortran Online Tutorials from PCDS, which helps you to learn out the professional language Fortran and makes our career in the future. Program for bisection method in fortran professional# program illustrates the bisection method in Cn) printf(x3 + 3x - 5 0n) double x0,x1 printf(Enter the first approximation to the rootn). Prints root of solution(x) with error in EPSILON An example function whose solution is determined using Print "You have not assumed right a and b "Įlse if solution(c)*solution(a) In function int main()ĭeclare and Initialize inputs a =-500, b = 100.
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